Webf ( x) = 2 – 3 x , x ∈ R , x > 0 The values of f ( x) for various values of real numbers x > 0 can be written in the tabular form as Thus, it can be clearly observed that the range of f is the set of all real numbers less than 2. i.e., range of f = (– ∞, 2) Alter: Let x > 0 ⇒ 3 x > 0 ⇒ 2 –3 x < 2 ⇒ f ( x) < 2 ∴Range of f = (– ∞, 2) WebSolution: Function f: R → R is defined by f (x) = ex. Let x1, x2 ∈ R and f (x1) = f (x2) or ex1 = ex2 or x1 = x2. Therefore, f is one-one. Let f (x) = ex = y. Taking log on both sides, we get x = logy. We know that negative real numbers have no pre-image or the function is not onto and zero is not the image of any real number.
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WebUsing the "partitioning the range of f" philosophy, the integral of a non-negative function f : R → R should be the sum over t of the areas between a thin horizontal strip between y = t and y = t + dt. This area is just μ{ x : f(x) > t} dt. Let f ∗ (t) = μ{ x : f(x) > t}. The Lebesgue integral of f is then defined by WebOct 31, 2024 · Find the range of the function f (x) = (x2 - 3x + 2)/ (x2 + x - 6) functions jee jee mains 1 Answer +1 vote answered Oct 31, 2024 by Raghab (50.8k points) selected Nov 4, 2024 by faiz Best answer Also, when x = 2, then y = 1/5 Hence, the range is R – {1, 1/5}. ← Prev Question Next Question → Find MCQs & Mock Test JEE Main 2024 Test Series crp instructions mn
4.7: Domain and Range of a Function - Mathematics LibreTexts
WebModified 8 years, 11 months ago. Viewed 218 times. 0. The function below is defined for continuous domains. Sketch the graph and state the range of the function. Question: f ( x) = 3 x + 2 for the domain { x ∈ R: x > 0 } The straight line cuts the y -axis at ( 2, 0) but since x > 0 why is the answer for the range still f ( x) > 2? WebThe domain of any expression is set to all the real numbers, except where the expression is undefined. In the expression f (x) = 3x - 2, the domain is all real numbers and the graph of the function will be a straight line without discontinuities. The domain of f (x) = 3x - 2 is {x x is a real number} and this can be denoted as ( - ∞, ∞ ... Web3. Let x ∈ R satisfy x 7 + 5 x 2-3 = 0. Then x is not a rational number. Solution We use proof by contradiction. Suppose x 7 + 5 x 2-3 = 0 and x is rational, so we can write x = a b where a, b ∈ Z, b > 0 with gcd(a, b) = 1. Then a b 7 + 5 a b 2-3 = 0 a 7 + 5 a 2 b 5-3 b 7 = 0 Since a and b have no common factors, they cannot both be even ... build it toilet sets