Chip's 7o
WebMar 3, 2024 · If the chip thickness and the uncut chip thickness during turning are 1.5 mm and 0.75 mm, respectively, then the shear force is N (round off to two decimal places). Q8. In an orthogonal cutting operation, shear angle = 11.31°, cutting force = 900 N and thrust force = 810 N. Then the shear force will be approximately (given sin 11.31° = 0.2) Q9. WebThe CHIP Agency may provide that children who have been determined eligible under the state plan shall remain eligible, regardless of any changes in the family’s circumstances, …
Chip's 7o
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Web1.During plain turning mild steel by a tool of geometry, 0o, 0o, 8o, 7o,15o, 90o, 0 (mm) at so= 0.2 mm/rev, the chip thickness was found tobe 0.5 mm. Determine the values of ? and ßo in the above case. be 0.5 mm. Determine the values of ? and ßo in the above case.
WebThe width of cut and uncut thickness are 2 mm and 0.2 mm respectively. If the average p y g value of coefficient of friction between the tool and the chip is 0.5 and the shear stress of the work material is 400 N/mm2, Determine (i) shear angle and [Ans. 36.7o (ii) Cutting and thrust component of the machine on force. [Ans.
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