WebNov 12, 2016 · Substitute 1 − sin2(θ) for cos2(θ): 2(1 −sin2(θ)) +3sin(θ) = 0. Use the distributive property: 2 − 2sin2(θ)) + 3sin(θ) = 0. Multiply both side by -1: 2sin2(θ)) −3sin(θ) −2 = 0. This is a quadratic where the variable is sin(θ). It looks like it will factor: # (sin (theta) - 2) (2sin (theta) + 1) = 0. WebApr 5, 2024 · Complete step-by-step answer: In the question we are given an equation which is. sin 3 θ + cos 2 θ = 0. and we have to find general solutions or values of. θ. for which equation satisfies. So, we are given as, sin …

Solving $2\\sin\\theta\\cos\\theta + \\sin\\theta = 0$

WebThe general solution of sin θ = 0 is θ = nπ, n∈Z and tan θ = tan α is θ = nπ + α, n∈Z. ∴ The required general solution is `θ/(2)` = nπ, n∈Z or `θ/(2)` = nπ + `pi/(4)`, n∈Z. i.e. θ = 2nπ, n∈Z or θ = `2nπ + pi/(2)`, n∈Z. Concept: Trigonometric Equations and Their Solutions. WebFeb 1, 2024 · 2 sin θ cos θ + sin θ = 0. I missed the obvious sin factorisation so proceeded as below. I see the correct solutions should be ± 2 / 3 π and the values when sin θ = 0. Although I missed the early factorisation I don't know what I'm doing to actually arrive at an incorrect answer: (1) 2 sin θ cos θ + sin θ = 0 (square) (2) 4 sin 2 θ ... restoring ross

trigonometry - General Solution of $\sin\theta=3\cos\theta ...

WebJul 30, 2024 · 2. In your last step you are almost there. You have. This gives. So either. Thus. Giving the solution. As others have pointed out, you could have gotten there … WebJun 15, 2015 · So assuming theta = x and T = 2pi: sintheta = 1 with theta = (pi)/2 pm 2npi AA n in ZZ (sintheta = 1 with theta = (pi)/2 pm 2npi for all n in the numerical set called … restoring rusty straight razor